Thursday, September 6, 2012

Algebra ll Style

I find math to be quite easy considering it runs through the family, but otherwise it gets rather irritating. One thing I found simple and easy to do after it being taught were inequalities. In addition, absolute value inequalities, but weren't as simplistic as normal. Absolute value inequalities are a mix of absolute value and compound inequalities. An example of a normal inequality is 7-3x < or equal to 2x+6. An example of an absolute value inequality is |2n + 1| < 9.

The first step to solving 7 - 3x < or equal to 2x + 6is getting x on one side and constants on the other. First you would subtract the 6 from the right to the left, vice versa with -3x(add instead of sub.) to the right. You should then get 1 < or equal to 5x. Next you just divide both sides by 5 to get x > or equal to 1/5.

The first step to solving an absolute value inequality is to isolate it everything in the value bars from the rest. |2n + 1| < 9 is already isolated so next is to determine if it is one of two inequalities, an “AND” or an “OR”. You determine this after the inequality is isolated by looking at the symbol. < means it’s an AND, > means it is an OR. |2n + 1| < 9 is an AND because of the symbol. After this you must solve this twice, first time with the original inequality, the second time with a flipped symbol and changed signs on the constant(s). |2n + 1| < 9, now you subtract the 1 to the right side leaving just 2n. Last you divide by 2 to both sides to get n < 4. Now to start the second part of the problem with |2n + 1| > -9. Same as before just subtract 1 to the right side leaving 2n > -10. Now divide both by 2 giving you n > -5. The compound inequality now looks like -5 < n < 4.

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